Jane did the following:

* 3a + b = 3ab

* 2s + 4t = 6st

Do you think Jane is correct in her algebraic manipulations?

If yes, please write down examples to show that her answer is correct.

If not, explain to Jane her mistakes and help her to correct

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To those who have posted your responses: You have correctly pointed out that Jane has mixed up the 2 operations "+" with "X".

Would you be able to tell us a SPECIAL CASE when 2s + 4t equals 6st?

That is, what are possible values of s and t if 2s + 4t is equal to 6st?

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ReplyDelete2s+4t=6st if s=2 and t=1/2. As long as s is 4 times t, the equation is possible.

ReplyDelete1.No. Jane has mixed up the 2 operations "+" with "X"

ReplyDelete2.When s and/or t is 1.

It could be possible if s and t were both of the value 1.

ReplyDeleteyes, 's' and 't' both could have a value of 1.

ReplyDeleteThis comment has been removed by the author.

ReplyDelete1)No she is wrong, as a and b or s and t represent different values, thus she cannot write ab or st. She can only do that if the order of operation is multiplication and not addition.

ReplyDelete2) One such case is possible when s is 4 and t is 1.

There are many cases, if s and t are 1, or s is 2 and t is 0.5, or if s is 1.5 and t is 0.75.

ReplyDeleteYes if 's' and 't' have the value of 1

ReplyDeleteThat is only possible when the values of both "s" and "t" are the same.

ReplyDelete1.No. Jane has mixed up the 2 operations "+" and "X"

ReplyDeleteThe special case would be if the value of both variables are 1 and so, this equation would work.Even if one of the variables is 1, the equation is still wrong.

ReplyDeleteNo. Jane has mixed up the 2 operations "+" with "X".When S or T is 1 it is possible.

ReplyDeleteIt would have been possible only if the values of s and t equals to 1.

ReplyDeleteThe special case is when 6(s X t) = 2s + 4t

ReplyDeletePossible value : s= 1 t= 1

As 2 + 4 = 6 and s X t = 1, 6(s X t)= 6 X 1 = (2 X 1) +( 4 X 1)

No. Jane has mixed up the 2 operations "+" with "X".

ReplyDeleteSecond question dunno

1. It may be possible depending on the number.

ReplyDelete2. s/t = 1

When s and t have the positive value of 1.

ReplyDeleteIt would be possible it t and s would have the exact same value.

ReplyDeleteIf both s and t = 1, the equation is possible.

ReplyDelete2s + 4t = 2x1 + 4x1

= 6

6st = 6 x 1 x 1

= 6.

No. Jane mixed up the 2 operations.

ReplyDeletePossible if tbe value of 's' is x4 the value of 't'

And i think you cannot use 2 different algebra to represent the same value...

ReplyDeleteIt would be possible if s and t are both 1

ReplyDelete