### (Follow-up) Chapter 4: Algebra... Help! What's Wrong?

Jane did the following:

* 3a + b = 3ab
* 2s + 4t = 6st

Do you think Jane is correct in her algebraic manipulations?
If yes, please write down examples to show that her answer is correct.

If not, explain to Jane her mistakes and help her to correct
~~~~~~~~~~~~
To those who have posted your responses: You have correctly pointed out that Jane has mixed up the 2 operations "+" with "X".

Would you be able to tell us a SPECIAL CASE when 2s + 4t equals 6st?
That is, what are possible values of s and t if 2s + 4t is equal to 6st?

1. This comment has been removed by the author.

2. 2s+4t=6st if s=2 and t=1/2. As long as s is 4 times t, the equation is possible.

3. 1.No. Jane has mixed up the 2 operations "+" with "X"
2.When s and/or t is 1.

4. It could be possible if s and t were both of the value 1.

5. yes, 's' and 't' both could have a value of 1.

6. This comment has been removed by the author.

7. 1)No she is wrong, as a and b or s and t represent different values, thus she cannot write ab or st. She can only do that if the order of operation is multiplication and not addition.
2) One such case is possible when s is 4 and t is 1.

8. There are many cases, if s and t are 1, or s is 2 and t is 0.5, or if s is 1.5 and t is 0.75.

9. Yes if 's' and 't' have the value of 1

10. That is only possible when the values of both "s" and "t" are the same.

11. 1.No. Jane has mixed up the 2 operations "+" and "X"

12. The special case would be if the value of both variables are 1 and so, this equation would work.Even if one of the variables is 1, the equation is still wrong.

13. No. Jane has mixed up the 2 operations "+" with "X".When S or T is 1 it is possible.

14. It would have been possible only if the values of s and t equals to 1.

15. The special case is when 6(s X t) = 2s + 4t
Possible value : s= 1 t= 1
As 2 + 4 = 6 and s X t = 1, 6(s X t)= 6 X 1 = (2 X 1) +( 4 X 1)

16. No. Jane has mixed up the 2 operations "+" with "X".
Second question dunno

17. 1. It may be possible depending on the number.
2. s/t = 1

18. When s and t have the positive value of 1.

19. It would be possible it t and s would have the exact same value.

20. If both s and t = 1, the equation is possible.
2s + 4t = 2x1 + 4x1
= 6
6st = 6 x 1 x 1
= 6.

21. No. Jane mixed up the 2 operations.
Possible if tbe value of 's' is x4 the value of 't'

22. And i think you cannot use 2 different algebra to represent the same value...

23. It would be possible if s and t are both 1