Method 1: 32 X 162 = 5184square root of 5184 = 72Method 2: Let y be the number.y X y = y ^2y^2 = 32 X 162y^2 = 518472^2 = 5184Answer = 72
Method 1: We multiply the 2 values by each other to get the product. 32x162=5184 Next, we take the square root of 5184 which is 72*.Method 2: We can prime factorise the 2 values and get the HCF, then we can find a number that has a common HCF with these 2 numbers and is also a multiple of 5184, then we can multiply it by itself and see if it is correct.
Method 1: 32 X 162 = 5184square root of 5184 = 72Method 2 :Prime factorisation of 32 and 162 is 2^5 and 2 x 3^4so when u multiply them it will get 2^6 X 3^4 so the square root of 2^6 X 3^4 = 2^3 X 3^2 = 72
1. 32 X 162 = 5184 5184 = 72 * 722.The prime factorisation of 32 and 162 is 2^5 and 2 * 3^4so when you multiply them it will get 2^6 * 3^4 and 2^6 X 3^4 = 2^3 * 3^2= 72
1. The first method is to take 32 x 162 to get the product of 5184. After that, take 5184 and square root it. the answer produced would be 72.2. The second method is to prime factorise the numbers 32 and 162 which will give 2^5 and 2x3^4 respectively and is equal to 2^6x3^4. To get the answer, grouping can be used. (2^3x3^2)(2^3x3^2) is still equal to 2^6x3^4. Answer is 2^3x3^2 which is 72.
Method 1: 32X162=5184square root of 5184= 72Method 2:prime factorization of 32= 2^5prime factorization or 162= 2*3^4(2^6X3^2)=(2^3X3^2)X(2^3X3^2)(2^3X3^2)=72
Oops too late D:Method 1: 32 X 162 = 5184Square root of 5184 = 72Method 2:Prime Factorization of 32 and 162 leads to 3 sets of (2^3X3^2) = 72
Method 1: Multiply 32 with 162, which equals to 5148, then square root 5148 to get 72.orMethod 2:Prime factorise the two numbers 32 and 162, which equals to (2^5) X (2x 3^4)Then multiply them together, which will equals to (2^6 x 3^4) and that equals to 72. Same answer.(>< late)
method 1: multiply 32 and 162 and square root the answer and you will get 72method 2:Prime factorise both numbers and find the LCM which will be (2^6*3^4) which will equate to 72 again.
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1st Method:32 x 162 = 51845184 (Squareroot) = 722nd Method:32 and 162 (Prime Factorise) = 2^6 x 3^4 (Squareroot) = 723rd Method:Repeatedly press the calculator and hope for the right digit :D
Method 1: Find Square Root of product __________} 32x162=72 (Ans)Method 2: Prime factorise then find cube root32 and 162 = (2^3 x 3^2) x 3(2^3 x 3^2) = 72 (Ans)
Method 1 is direct, and the answer could be easily evaluated using the calculator. All of you were correct :)For method 2, all of you also pointed out correctly that we could use Prime Factorisation method. This becomes very handy when calculator is not available. More importantly, it checks our understanding:To find square root of a number, the Prime factors could be organised into 2 groups.>> Mervin & "Mitsunari Ishida": Why expressed the factors in 3 groups?>> Luke: How does HCF come into the picture?>> Ben: When repeating pressing the calculator, would you be doing it in some systematic way? If you could describe that, it could be one method, too :)Amongst those who describe the Prime Factorisation method, Amelia is the first who have described the concept behind the square root. Well done :)